Hi all! I have a query regarding Xilinx FPGAs and the XST. In many documents relating FPGA designs, there are such statements as: BUFG instance_name (.O (user_O), .I (user_I)); My question is that do we really need to instantiate BUFG, IBUFG etc in this manner? Isn't this automatically done by the tool(XST etc)? Lets say i am using a clk signal in my design. I LOC this clk signal to one of FPGAs IGCLK pad. Wont' the IBUFG primitive be used automatically? Similarly, does the tool not automatically insert IBUF and OBUF at the input/output signals? Thanks
IBUF, IBUFG, OBUF
Started by ●September 16, 2003
Reply by ●September 16, 20032003-09-16
In principle is as you said, but my experience is that XST get confused pretty quickly when your design is more complicated than just having a clk signal LOCed to one IGCLK pad. So I prefer to instantiate all BUFG, IBUFG etc, to have full control. This is not usually necessary for normal I/Os (unless they are bidir, tristate, special voltage levels etc) Tullio On 15 Sep 2003, rider wrote:> I have a query regarding Xilinx FPGAs and the XST. In many documents > relating FPGA designs, there are such statements as: > > BUFG instance_name (.O (user_O), > .I (user_I)); > > My question is that do we really need to instantiate BUFG, IBUFG etc > in this manner? Isn't this automatically done by the tool(XST etc)? > Lets say i am using a clk signal in my design. I LOC this clk signal > to one of FPGAs IGCLK pad. Wont' the IBUFG primitive be used > automatically? Similarly, does the tool not automatically insert IBUF > and OBUF at the input/output signals? > > Thanks