Hi,

I have a matlab code and I have to convert it to verilog.The matlab code is as follows:

/****************************************************************/

clc;

clear all;

close all;

delt = 5;
carr_phase_s = 0;
for i = 1:1:30
    carr_phase_s = carr_phase_s + delt;
    if(carr_phase_s >= 26)
        carr_phase_s = carr_phase_s - 26;
    end
end

output in Matlab: 5 10 15 20 4 9 14 19 24 3 8 13 18 23 2 7 12 17 22 1 6 11 16 21 0 5 10 15 20

/*****************************************************************/

I have written a verilog equivalent for it. It is as follows:

module TestCode(
    );
     reg clk=0;
always#5 clk=~clk;
reg [2:0] delt=5;
reg [5:0] carr_phase_s=0;
always@(posedge clk)
begin
carr_phase_s<=carr_phase_s+delt;
carr_phase_s_d<=carr_phase_s;
    if(carr_phase_s>=26)
    begin
    carr_phase_s_d<=carr_phase_s-26;
    carr_phase_s<=carr_phase_s-26;
    end
    
end
endmodule

Output in simulation  of Xilinx ISE/Vivado software:
carr_phase_s_d =0  5  10  15  20  25  4  4  9  14  19  24   3  3  8  13  18  23  2  2 7  12  17  22  1   1  6 11   16  21  0  0  5  10  15  20

As, one can see there is repetition of the value whenever carr_phase_s is crossing the boundary.

Some one help me in properly converting this piece of code, so that the output of both Matlab and Verilog match perfectly?

Thanks.

I think this could be one way.

always@(posedge clk)
begin
    if(carr_phase_s + delt >= 26)
      carr_phase_s <= (carr_phase_s + delt) -26;
    else
      carr_phase_s<=carr_phase_s + delt;
end