FPGARelated.com
Forums
   Forums    More Forums    comp.arch.fpga  

Questions about counter in VHDL

Started by Unknown ●March 7, 2006
I have implemented a 8-bit synchronous counter by VHDL. The result is
that the LED display show  continuously running the count from 0 to
F(in Hex). Now, I need to change the result which the LED display can
count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
answer me? Thanks a lot!!
The following VHDL code are about 8-bit synchronous counter:
Library IEEE;
USE IEEE.std_logic_1164.all;
USE IEEE.std_logic_arith.all;
USE IEEE.std_logic_unsigned.all;

ENTITY counter_eg IS
	PORT(
	       PB1, clk_25MHz                           : IN std_logic;
          led0, led1, led2, led3, led4, led5, led6  : OUT std_logic);
END counter_eg;

ARCHITECTURE c OF counter_eg IS

COMPONENT counter
		PORT(
			Clock, Reset	: IN  std_logic;
			count		: OUT std_logic_vector(3 DOWNTO 0));

		END COMPONENT;

	COMPONENT dec_7seg
		PORT(
			hex_digit	   : IN	 std_logic_vector(3 DOWNTO 0);
			segment_a, segment_b, segment_c, segment_d, segment_e,
			segment_f, segment_g   : OUT std_logic);
	END COMPONENT;

	COMPONENT clk_div
		PORT(
			clock_25MHz		: IN	std_logic;
			clock_1MHz		: OUT	std_logic;
		   	clock_100KHz		: OUT	std_logic;
		   	clock_10KHz		: OUT	std_logic;
			clock_1KHz		: OUT	std_logic;
			clock_100Hz		: OUT	std_logic;
			clock_10Hz		: OUT	std_logic;
			clock_1Hz			: OUT	std_logic);
	END COMPONENT;

	SIGNAL count    : std_logic_vector(3 DOWNTO 0);
	SIGNAL clk_1KHz : std_logic;
BEGIN
	c0: clk_div  port map (clock_25MHz=> clk_25MHz, clock_1KHz=>clk_1KHz);
	c1: counter  port map (clock=>clk_1KHz, reset=>PB1, count=> count);
	c2: dec_7seg port map (count, led0, led1, led2, led3, led4, led5,
led6);
	
END c;
Reply by Alan Myler ●March 7, 20062006-03-07

sandypure@yahoo.com wrote:


> I have implemented a 8-bit synchronous counter by VHDL. The result is
> that the LED display show  continuously running the count from 0 to
> F(in Hex). Now, I need to change the result which the LED display can
> count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
> answer me? Thanks a lot!!
> The following VHDL code are about 8-bit synchronous counter:
> Library IEEE;
> USE IEEE.std_logic_1164.all;
> USE IEEE.std_logic_arith.all;
> USE IEEE.std_logic_unsigned.all;
> 
> ENTITY counter_eg IS
> 	PORT(
> 	       PB1, clk_25MHz                           : IN std_logic;
>           led0, led1, led2, led3, led4, led5, led6  : OUT std_logic);
> END counter_eg;
> 
> ARCHITECTURE c OF counter_eg IS
> 
> COMPONENT counter
> 		PORT(
> 			Clock, Reset	: IN  std_logic;
> 			count		: OUT std_logic_vector(3 DOWNTO 0));
> 
> 		END COMPONENT;
> 
> 	COMPONENT dec_7seg
> 		PORT(
> 			hex_digit	   : IN	 std_logic_vector(3 DOWNTO 0);
> 			segment_a, segment_b, segment_c, segment_d, segment_e,
> 			segment_f, segment_g   : OUT std_logic);
> 	END COMPONENT;
> 
> 	COMPONENT clk_div
> 		PORT(
> 			clock_25MHz		: IN	std_logic;
> 			clock_1MHz		: OUT	std_logic;
> 		   	clock_100KHz		: OUT	std_logic;
> 		   	clock_10KHz		: OUT	std_logic;
> 			clock_1KHz		: OUT	std_logic;
> 			clock_100Hz		: OUT	std_logic;
> 			clock_10Hz		: OUT	std_logic;
> 			clock_1Hz			: OUT	std_logic);
> 	END COMPONENT;
> 
> 	SIGNAL count    : std_logic_vector(3 DOWNTO 0);
> 	SIGNAL clk_1KHz : std_logic;
> BEGIN
> 	c0: clk_div  port map (clock_25MHz=> clk_25MHz, clock_1KHz=>clk_1KHz);
> 	c1: counter  port map (clock=>clk_1KHz, reset=>PB1, count=> count);
> 	c2: dec_7seg port map (count, led0, led1, led2, led3, led4, led5,
> led6);
> 	
> END c;
> 



I'm not going to do your homework for you but here's a suggestion, how 
about decoding when the count equals 9 and using this to reset your 
counter. For your percentage I'm sure you can figure out how to code 
that in your vhdl.

Alan
Reply by Aurelian Lazarut ●March 7, 20062006-03-07

sandypure@yahoo.com wrote:

> I have implemented a 8-bit synchronous counter by VHDL.


I'll give you a hint, the counter is not in this file, only the 
intantiation of the counter.
but you can decode count=10 and trigger a reset. (in this file)
as Alan just said.

Aurash

  The result is

> that the LED display show  continuously running the count from 0 to
> F(in Hex). Now, I need to change the result which the LED display can
> count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
> answer me? Thanks a lot!!
> The following VHDL code are about 8-bit synchronous counter:
> Library IEEE;
> USE IEEE.std_logic_1164.all;
> USE IEEE.std_logic_arith.all;
> USE IEEE.std_logic_unsigned.all;
> 
> ENTITY counter_eg IS
> 	PORT(
> 	       PB1, clk_25MHz                           : IN std_logic;
>           led0, led1, led2, led3, led4, led5, led6  : OUT std_logic);
> END counter_eg;
> 
> ARCHITECTURE c OF counter_eg IS
> 
> COMPONENT counter
> 		PORT(
> 			Clock, Reset	: IN  std_logic;
> 			count		: OUT std_logic_vector(3 DOWNTO 0));
> 
> 		END COMPONENT;
> 
> 	COMPONENT dec_7seg
> 		PORT(
> 			hex_digit	   : IN	 std_logic_vector(3 DOWNTO 0);
> 			segment_a, segment_b, segment_c, segment_d, segment_e,
> 			segment_f, segment_g   : OUT std_logic);
> 	END COMPONENT;
> 
> 	COMPONENT clk_div
> 		PORT(
> 			clock_25MHz		: IN	std_logic;
> 			clock_1MHz		: OUT	std_logic;
> 		   	clock_100KHz		: OUT	std_logic;
> 		   	clock_10KHz		: OUT	std_logic;
> 			clock_1KHz		: OUT	std_logic;
> 			clock_100Hz		: OUT	std_logic;
> 			clock_10Hz		: OUT	std_logic;
> 			clock_1Hz			: OUT	std_logic);
> 	END COMPONENT;
> 
> 	SIGNAL count    : std_logic_vector(3 DOWNTO 0);
> 	SIGNAL clk_1KHz : std_logic;
> BEGIN
> 	c0: clk_div  port map (clock_25MHz=> clk_25MHz, clock_1KHz=>clk_1KHz);
> 	c1: counter  port map (clock=>clk_1KHz, reset=>PB1, count=> count);
> 	c2: dec_7seg port map (count, led0, led1, led2, led3, led4, led5,
> led6);
> 	
> END c;
>
Reply by Symon ●March 7, 20062006-03-07
<sandypure@yahoo.com> wrote in message 
news:1141751267.321930.165700@v46g2000cwv.googlegroups.com...

>I have implemented a 8-bit synchronous counter by VHDL. The result is
> that the LED display show  continuously running the count from 0 to
> F(in Hex). Now, I need to change the result which the LED display can
> count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
> answer me? Thanks a lot!!
>

How about gating the clock to something really fast when the count is 10 - 
15 inclusive. The A-F will whizz by so fast, no-one will notice.
If you get that to work, you deserve extra marks.
HTH, Syms.
Reply by ●March 7, 20062006-03-07
Alan,
I want to ask how to decode in vhdl? When the count is at 9, press
reset button is go back to 0 again.


Alan Myler =E5=AF=AB=E9=81=93=EF=BC=9A


> sandypure@yahoo.com wrote:
>
> > I have implemented a 8-bit synchronous counter by VHDL. The result is
> > that the LED display show  continuously running the count from 0 to
> > F(in Hex). Now, I need to change the result which the LED display can
> > count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
> > answer me? Thanks a lot!!
> > The following VHDL code are about 8-bit synchronous counter:
> > Library IEEE;
> > USE IEEE.std_logic_1164.all;
> > USE IEEE.std_logic_arith.all;
> > USE IEEE.std_logic_unsigned.all;
> >
> > ENTITY counter_eg IS
> > 	PORT(
> > 	       PB1, clk_25MHz                           : IN std_logic;
> >           led0, led1, led2, led3, led4, led5, led6  : OUT std_logic);
> > END counter_eg;
> >
> > ARCHITECTURE c OF counter_eg IS
> >
> > COMPONENT counter
> > 		PORT(
> > 			Clock, Reset	: IN  std_logic;
> > 			count		: OUT std_logic_vector(3 DOWNTO 0));
> >
> > 		END COMPONENT;
> >
> > 	COMPONENT dec_7seg
> > 		PORT(
> > 			hex_digit	   : IN	 std_logic_vector(3 DOWNTO 0);
> > 			segment_a, segment_b, segment_c, segment_d, segment_e,
> > 			segment_f, segment_g   : OUT std_logic);
> > 	END COMPONENT;
> >
> > 	COMPONENT clk_div
> > 		PORT(
> > 			clock_25MHz		: IN	std_logic;
> > 			clock_1MHz		: OUT	std_logic;
> > 		   	clock_100KHz		: OUT	std_logic;
> > 		   	clock_10KHz		: OUT	std_logic;
> > 			clock_1KHz		: OUT	std_logic;
> > 			clock_100Hz		: OUT	std_logic;
> > 			clock_10Hz		: OUT	std_logic;
> > 			clock_1Hz			: OUT	std_logic);
> > 	END COMPONENT;
> >
> > 	SIGNAL count    : std_logic_vector(3 DOWNTO 0);
> > 	SIGNAL clk_1KHz : std_logic;
> > BEGIN
> > 	c0: clk_div  port map (clock_25MHz=3D> clk_25MHz, clock_1KHz=3D>clk_1K=

Hz);

> > 	c1: counter  port map (clock=3D>clk_1KHz, reset=3D>PB1, count=3D> coun=

t);

> > 	c2: dec_7seg port map (count, led0, led1, led2, led3, led4, led5,
> > led6);
> >
> > END c;
> >
>
>
> I'm not going to do your homework for you but here's a suggestion, how
> about decoding when the count equals 9 and using this to reset your
> counter. For your percentage I'm sure you can figure out how to code
> that in your vhdl.
>=20
> Alan
Reply by ●March 7, 20062006-03-07
gating the clcok?? i don't understand!! Can you explain? Thanks!!
Reply by ●March 7, 20062006-03-07
Symon,
gating the clcok?? i don't understand!! Can you explain? Thanks!!
Reply by Symon ●March 7, 20062006-03-07
Sorry Laura, I was being sarcastic. Of course, gating the clock is BAD! 
Almost as bad as asking people on a newsgroup to do your homework for you! 
;-)
Cheers, Syms.
<laura_pretty05@yahoo.com.hk> wrote in message 
news:1141754026.219843.19920@z34g2000cwc.googlegroups.com...

> Symon,
> gating the clcok?? i don't understand!! Can you explain? Thanks!!
>
Reply by Jim Granville ●March 7, 20062006-03-07
Symon wrote:

> <sandypure@yahoo.com> wrote in message 
> news:1141751267.321930.165700@v46g2000cwv.googlegroups.com...
> 
>>I have implemented a 8-bit synchronous counter by VHDL. The result is
>>that the LED display show  continuously running the count from 0 to
>>F(in Hex). Now, I need to change the result which the LED display can
>>count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
>>answer me? Thanks a lot!!
>>
> 
> How about gating the clock to something really fast when the count is 10 - 
> 15 inclusive. The A-F will whizz by so fast, no-one will notice.
> If you get that to work, you deserve extra marks.
> HTH, Syms. 


  That would only appear to count 0..9, a smart marker might say it still
shows A..F  just that your eye cannot resolve it...
  I think the answer is to re-write the FONT ROM code, so it only 
displays  0..9 - This would even pass a cursory test. ;)
  - and it appears to fully meet the wording of the spec...
-jg
Reply by ●March 8, 20062006-03-08
hi, Aurelian Lazarut
I still don't understand what you means. How to decode in VHDL?
The following are my counter VHDL code:
Library IEEE;
USE IEEE.std_logic_1164.all;
USE IEEE.std_logic_arith.all;
USE IEEE.std_logic_unsigned.all;


Entity Counter IS
Port
    ( Clock, Reset	:IN  std_logic;
     count	                : OUT std_logic_vector(3 DOWNTO 0));
END Counter;

ARCHITECTURE a OF Counter IS
	SIGNAL internal_count:  std_logic_vector(3 DOWNTO 0);

BEGIN
	count <=3D internal_count;
	Process (Reset, Clock)
    BEGIN
	IF Reset=3D'0' THEN
	internal_count <=3D "0000";
	ELSIF (Clock'EVENT AND clock=3D'1') THEN
	 internal_count <=3D internal_count + 1;
	END IF;
    END Process;
END a;

from Laura


Aurelian Lazarut =E5=AF=AB=E9=81=93=EF=BC=9A


> sandypure@yahoo.com wrote:
> > I have implemented a 8-bit synchronous counter by VHDL.
>
> I'll give you a hint, the counter is not in this file, only the
> intantiation of the counter.
> but you can decode count=3D10 and trigger a reset. (in this file)
> as Alan just said.
>
> Aurash
>
>   The result is
> > that the LED display show  continuously running the count from 0 to
> > F(in Hex). Now, I need to change the result which the LED display can
> > count  from 0 to 9 only. How can I change in the VHDL code? Can anyone
> > answer me? Thanks a lot!!
> > The following VHDL code are about 8-bit synchronous counter:
> > Library IEEE;
> > USE IEEE.std_logic_1164.all;
> > USE IEEE.std_logic_arith.all;
> > USE IEEE.std_logic_unsigned.all;
> >
> > ENTITY counter_eg IS
> > 	PORT(
> > 	       PB1, clk_25MHz                           : IN std_logic;
> >           led0, led1, led2, led3, led4, led5, led6  : OUT std_logic);
> > END counter_eg;
> >
> > ARCHITECTURE c OF counter_eg IS
> >
> > COMPONENT counter
> > 		PORT(
> > 			Clock, Reset	: IN  std_logic;
> > 			count		: OUT std_logic_vector(3 DOWNTO 0));
> >
> > 		END COMPONENT;
> >
> > 	COMPONENT dec_7seg
> > 		PORT(
> > 			hex_digit	   : IN	 std_logic_vector(3 DOWNTO 0);
> > 			segment_a, segment_b, segment_c, segment_d, segment_e,
> > 			segment_f, segment_g   : OUT std_logic);
> > 	END COMPONENT;
> >
> > 	COMPONENT clk_div
> > 		PORT(
> > 			clock_25MHz		: IN	std_logic;
> > 			clock_1MHz		: OUT	std_logic;
> > 		   	clock_100KHz		: OUT	std_logic;
> > 		   	clock_10KHz		: OUT	std_logic;
> > 			clock_1KHz		: OUT	std_logic;
> > 			clock_100Hz		: OUT	std_logic;
> > 			clock_10Hz		: OUT	std_logic;
> > 			clock_1Hz			: OUT	std_logic);
> > 	END COMPONENT;
> >
> > 	SIGNAL count    : std_logic_vector(3 DOWNTO 0);
> > 	SIGNAL clk_1KHz : std_logic;
> > BEGIN
> > 	c0: clk_div  port map (clock_25MHz=3D> clk_25MHz, clock_1KHz=3D>clk_1K=

Hz);

> > 	c1: counter  port map (clock=3D>clk_1KHz, reset=3D>PB1, count=3D> coun=

t);

> > 	c2: dec_7seg port map (count, led0, led1, led2, led3, led4, led5,
> > led6);
> > =09
> > END c;
> >
You might also like... (promoted content)
The 2024 Embedded Online Conference - Register Early and Save with Promo Code ER2024!
The 2024 Embedded Online Conference - Register Early and Save with Promo Code ER2024!
The 2024 Embedded Online Conference - Register Early and Save with Promo Code ER2024!